A train train when moves at an average speed of 40 *kmph*, reaches its destination on time. When its average speed becomes 35 *kmph,* then it reaches its destination 15 minutes late. Find the length of journey.

- A.
**70***km* - B.
**80***km* - C.
**40***km* - D.
**20***km***Ans**: A.**Sol.**

Difference between timings = 15 min = 1/4 hr.

Let the length of journey be*x km*.

Then,*x*/35 –*x*/40 = 1/4

⇔ 8*x*– 7*x*= 70

⇔*x*= 70*km.*

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