The circumference of the front and back wheels of a vehicle are 6 3/14 m and 8 1/18 m respectively. At any given moment, a chalk mark is put on the point of contact of each wheel with the ground. Find the distance traveled by the vehicle so that both the chalk marks are again on the ground at the same time
Solution: The required distance is the LCM of 6 3/14 and 8 1/18
LCM of 6 3/14 and 8 1/18 = LCM (87/14, 145/18)
=> LCM(87,145) / HCF (14,18) = 435/2 = 217.5m
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