**The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: **

**127****125****175****155**

Sol.

Required number = H.C.F. of (1657 – 6) and (2037 – 5)

= H.C.F. of 1651 and 2032 = 127.

Answer 1

#### Author Profile

- At IBPS Preparation,We provide pathway for any candidate who wishes to shine in the recruitment process of IBPS.

##### Latest entries

- Exams2017.11.02Government Exams – The Critical One
- Announcements2017.09.06Recruitment Application for IBPS Clerk VII is out for Vacancies of 2018-19
- Announcements2017.08.30What to Expect for IBPS PO Prelims Exam 2017 (Important Topics)
- General Awareness2017.08.22Most Asked Questions about the President of India