Find the least number which when divided by 8, 9, 15, 24, 32 and 36 leaves remainders 3, 4, 10, 19,

Find the least number which when divided by 8, 9, 15, 24, 32 and 36 leaves remainders 3, 4, 10, 19, 27 and 31 respectively?

  1. 2880
  2. 2885
  3. 2974
  4. 2875
  5. None of these Ans: 4

    Solution:  We can assume that the difference between the numbers and their remainders is same i.e., 8-3 = 9-4 = 15-10 = 24-19 = 32-27 = 36-31 = 5
    So, required answer is: LCM (8, 9, 15, 24, 32, 36) – 5 = > 2880 – 5 = 2875

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