Find the largest number of four digits exactly divisible by 12,15,18 and 27.

Find the largest number of four digits exactly divisible by 12,15,18 and 27.

A. 5500
B. 9000
C.
7300                             
D.
9720

Answer: D

Solution:
The Largest number of four digits is 9999.

Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.

On dividing 9999 by 540,we get 279 as remainder .

\Required number = (9999-279) = 9720.

Author Profile

IBPS Preparation Team
IBPS Preparation Team
At IBPS Preparation,We provide pathway for any candidate who wishes to shine in the recruitment process of IBPS.
READ  H.C.F and L.C.M | Aptitude Question and Answer

Leave a Reply

Your email address will not be published. Required fields are marked *

2 + 7 =


IBPS Preparation © 2017