Find the largest number of four digits exactly divisible by 12,15,18 and 27.

Find the largest number of four digits exactly divisible by 12,15,18 and 27.

A. 5500
B. 9000
C.
7300                             
D.
9720

Answer: D

Solution:
The Largest number of four digits is 9999.

Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.

On dividing 9999 by 540,we get 279 as remainder .

\Required number = (9999-279) = 9720.

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