**Find **the largest number of four digits exactly divisible by 12,15,18 and 27.

**A.** 5500**B.** 9000**C.** 7300

**9720**

D.

D.

**Answer:** **D**

** Solution: **

The Largest number of four digits is 9999.

Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.

On dividing 9999 by 540,we get 279 as remainder .

\Required number = (9999-279) = **9720.**

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