Find the largest number of four digits exactly divisible by 12,15,18 and 27.

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Find the largest number of four digits exactly divisible by 12,15,18 and 27.

A. 5500
B. 9000
C.
7300                             
D.
9720

Answer: D

Solution:
The Largest number of four digits is 9999.

Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.

On dividing 9999 by 540,we get 279 as remainder .

\Required number = (9999-279) = 9720.

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