**Find **the largest number of four digits exactly divisible by 12,15,18 and 27.

**A.** 5500**B.** 9000**C.** 7300

**9720**

D.

D.

**Answer:** **D**

Solution:

The Largest number of four digits is 9999.

Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.

On dividing 9999 by 540,we get 279 as remainder .

\Required number = (9999-279) = **9720.**

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Paanch anko ki sabse badi sankhya gyat kare jisme yadi 45 jod de to wah sankhya 60, 65, 75, 80 se puri puri bibhaajit ho jayegi?

Plaese isaka pura solution bataiye.