**Find the greatest number which when divide 357, 192 and 252 leaves same remainder in each case**

- 45
- 1
- 15
- Cant be determinde
- None of these

**Ans:**3**Solution:**Required answer is :-HCF (357-192, 192-252, 357-252)

= > HCF (165, 60, 105) = 15

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