Find the greatest number which when divide 357, 192 and 252 leaves same remainder in each case

Find the greatest number which when divide 357, 192 and 252 leaves same remainder in each case

  1. 45
  2. 1
  3. 15
  4. Cant be determinde
  5. None of these
    Ans: 3
    Solution: Required answer is :-HCF (357-192, 192-252, 357-252)
                 = > HCF (165, 60, 105) = 15

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READ  Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

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