The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?

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The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?

  1. 1
  2. 20
  3. 0  
  4. 19

Answer: 4

Solution:

Average of 20 numbers = 0

==>Average of 20 numbers / 20  = 0

=> Sum of 20 numbers = 0

Hence at the most, there can be 19 positive numbers.

(Such that if the sum of these 19 positive numbers is x, 20th number will be -x)

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