**The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?**

- 1
- 20
- 0
- 19

Answer: 4

Solution:

Average of 20 numbers = 0

==>Average of 20 numbers / 20 = 0

=> Sum of 20 numbers = 0

Hence at the most, there can be 19 positive numbers.

(Such that if the sum of these 19 positive numbers is x, 20th number will be -x)

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